Sodium Hydroxide → (+-)-trans4-Methylene-2-phenylcyclopentanoic acid
반응식
[CH2:1]=[C:2]1[CH2:6][C@@H:5]([C:7]([O:9]C)=[O:8])[C@H:4]([C:11]2[CH:16]=[CH:15][CH:14]=[CH:13][CH:12]=2)[CH2:3]1.[OH-].[Na+]>CO>[CH2:1]=[C:2]1[CH2:6][C@@H:5]([C:7]([OH:9])=[O:8])[C@H:4]([C:11]2[CH:12]=[CH:13][CH:14]=[CH:15][CH:16]=2)[CH2:3]1참가 물질
4
반응 조건
- 온도
- 65 °C
실험 절차
To a solution of methyl (+−)-trans4-methylene-2-phenylcyclopentanoate prepared as in Example 1, Step A (28.4 g, 131 mmol) in methanol (400 mL) was added 5N sodium hydroxide (131 mL, 656 mmol). The reaction was heated at 65° C. for 1 h then cooled and concentrated. The residue was diluted with water, acidified with 2M hydrochloric acid and extracted twice with methylene chloride. The organic layers were each washed with brine, dried over sodium sulfate, combined and concentrated in vacuo to give the crude title acid (27.2 g) which was used directly in Step B.