Benzene → Tetraethylammonium 4-Nitrophenolate
반응식
[N+:1]([C:4]1[CH:9]=[CH:8][C:7]([OH:10])=[CH:6][CH:5]=1)([O-:3])=[O:2].C1C=CC=CC=1.[OH-].[CH2:18]([N+:20]([CH2:25][CH3:26])([CH2:23][CH3:24])[CH2:21][CH3:22])[CH3:19]>O>[N+:1]([C:4]1[CH:9]=[CH:8][C:7]([O-:10])=[CH:6][CH:5]=1)([O-:3])=[O:2].[CH2:18]([N+:20]([CH2:25][CH3:26])([CH2:23][CH3:24])[CH2:21][CH3:22])[CH3:19]참가 물질
5
실험 절차
A mixture of 4-nitrophenol (13.9 g, 0.10 mol) and benzene (250 mL) was treated with tetraethylammonium hydroxide (14.7 g, 0.10 mol), added as a 20% aqueous solution. The mixture was heated under reflux until all water was removed by azeotropic distillation. The solution was allowed to cool with continued stirring. Upon standing, 25.4 g of a yellow solid was obtained; it was recrystallized from THF. 1H NMR (CDCl3) confirmed the title compound.