Triphenylphosphine → HCID 59093854, 화합물

HRID 324600노트

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HRID 324600 반응식
[O:1]=[C:2]1[NH:6][C:5](=[O:7])[C:4]2([CH2:12][CH2:11][N:10]([C:13]([O:15][C:16]([CH3:19])([CH3:18])[CH3:17])=[O:14])[CH2:9][CH2:8]2)[NH:3]1.[CH3:20][O:21][C:22](=[O:46])[C@H:23]([CH2:44]O)[NH:24][C:25]([C:38]1[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=1)([C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1)[C:26]1[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=1.C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.N(C(OCC)=O)=NC(OCC)=O>C1COCC1>[CH3:20][O:21][C:22]([C@@H:23]([NH:24][C:25]([C:38]1[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=1)([C:26]1[CH:27]=[CH:28][CH:29]=[CH:30][CH:31]=1)[C:32]1[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=1)[CH2:44][N:6]1[C:5](=[O:7])[C:4]2([CH2:8][CH2:9][N:10]([C:13]([O:15][C:16]([CH3:19])([CH3:18])[CH3:17])=[O:14])[CH2:11][CH2:12]2)[NH:3][C:2]1=[O:1])=[O:46]

참가 물질

6

실험 절차

A solution of 3.6 g (13.37 mmol) of (34.2) in 15 ml of absolute THF is added to a solution of 3.72 g (10.3 mmol) of (34.3) and 3.5 g (13.34 mmol) of triphenylphosphine in 20 ml of absolute THF. 2.11 ml (13.37 mmol) of diethyl azodicarboxylate (DEAD) are added to this solution and the reaction mixture is stirred at room temperature until the reaction has come to an end. The solvent is removed in vacuo and the residue is chromatographed through silica gel using heptane/ethyl acetate. 6 g (95%) of (34.4) are obtained after concentrating the product fractions.

후처리

  1. customThe solvent is removed in vacuo
  2. customthe residue is chromatographed through silica gel

출처 및 근거

ORD 기록
ord-c3af4a3315e245ab93395b93a5e5a82d
출처 데이터셋
uspto-grants-2001_04
특허 번호
US06218415B1

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