Dimethylformamide → Acrylic Acid

반응식

Br[CH2:2]CCCCCCCCCCC[O:14]C1C=C[C:18]([C:19]([O:21]C2C=CC(OC(C)CC)=CC=2)=[O:20])=[CH:17]C=1.[CH3:35][N:36]([CH:38]=O)[CH3:37]>>[C:19]([OH:21])(=[O:20])[CH:18]=[CH2:17].[OH-:14].[CH3:35][N+:36]([CH3:38])([CH3:2])[CH3:37]

참가 물질

반응물 2

HCID 6228Dimethylformamide

HCID 197340594-(1-Methylpropoxy)phenyl 4-(12-bromododecyloxy)benzoate

생성물 2

HCID 6581Acrylic Acid

HCID 60966Tetramethylammonium hydroxide

실험 절차

A solution of 6 mmol (3.2 g) of the bromo compound obtained in (2), 10 mmol (0.72 g) of acrylic acid, and 10 mmol (1.8 g) of tetramethylammonium hydroxide (pentahydrate) in 30 ml of DMF was stirred for 10 hours at room temperature. To the resulting reaction solution was added water and then extracted with ether. The extract was concentrated, and the concentrate was purified by column chromatography to obtain 2.2 g of the objective monomer (3b). (Yield: 71%)

출처 및 근거

ORD 기록: ord-64dcca14c6b846159878a76c5190a56e
출처 데이터셋: uspto-grants-1993_12
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US05269963

반응 노트

불러오는 중…