Sodium Hydroxide → 5-Ethenyl-4-oxo-1,4-dihydroquinoline-2-carboxylic acid

HRID 326619노트

반응식

HRID 326619 반응식
[CH:1]([C:3]1[CH:12]=[CH:11][CH:10]=[C:9]2[C:4]=1[C:5](=[O:18])[CH:6]=[C:7]([C:13]([O:15]CC)=[O:14])[NH:8]2)=[CH2:2].[OH-].[Na+]>O>[CH:1]([C:3]1[CH:12]=[CH:11][CH:10]=[C:9]2[C:4]=1[C:5](=[O:18])[CH:6]=[C:7]([C:13]([OH:15])=[O:14])[NH:8]2)=[CH2:2]

참가 물질

4

반응물 2

HCID 14798Sodium HydroxideHCID 19735212Ethyl 5-ethenyl-4-oxo-1,4-dihydroquinoline-2-carboxylate

생성물 1

HCID 148427185-Ethenyl-4-oxo-1,4-dihydroquinoline-2-carboxylic acid수율 70.8%

시약·촉매·용매 1

HCID 962Water용매

실험 절차

Treatment of ethyl 5-ethenyl-4-oxo-1,4-dihydroquinoline-2-carboxylate (0.15 g) with sodium hydroxide (0.1 g), as described in Example 1c, gave 5-ethenyl-4-oxo-1,4-dihydroquinoline-2-carboxylic acid (0.094 g), mp 265°-266° C., δ (360 MHz, DMSO-d6) 5.24 and 5.54 (2H, 2dd, =CH2), 6.56 (1H, s, 3-H), 7.37 (1H, d, 6-H), 7.62 (1H, t, 7-H), 7.91 (1H, d, 8-H), 8.17 (1H, 2d, CH=) and 11.80 (1H, bs, NH), (Found: C, 66.43; H, 4.37; N, 6.37%, C12H9NO3. 0.1 H2O requires C, 66.35; H, 4.36; N, 6.44%).

출처 및 근거

ORD 기록
ord-c8902ca891cc49c4add15773088917ba
출처 데이터셋
uspto-grants-1993_12
특허 번호
US05270309

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