Sodium cyanoborohydride → 6-Chloro-5-methylthioindoline
반응식
[Cl:1][C:2]1[CH:10]=[C:9]2[C:5]([CH:6]=[CH:7][NH:8]2)=[CH:4][C:3]=1[S:11][CH3:12].C([BH3-])#N.[Na+]>>[Cl:1][C:2]1[CH:10]=[C:9]2[C:5]([CH2:6][CH2:7][NH:8]2)=[CH:4][C:3]=1[S:11][CH3:12]참가 물질
3
실험 절차
6-Chloro-5-methylthioindole (D47) (0.72 g, 3.65 mmol) was treated with sodium cyanoborohydride as in the method of Description 10 to give the title compound (0.72 g, 98%) as a pale yellow oil.
출처 및 근거
- ORD 기록
- ord-c3f24d915a3d42d1b09b54ad2d686ba6
- 출처 데이터셋
- uspto-grants-1998_11
- 특허 번호
- US05834494
반응 노트
불러오는 중…