Iodine → 3,4-Dibenzyloxy-6-iodobenzyl alcohol

반응식

[CH2:1]([O:8][C:9]1[CH:10]=[C:11]([CH:14]=[CH:15][C:16]=1[O:17][CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=1)[CH2:12][OH:13])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[I:25]I>C(Cl)(Cl)Cl.FC(F)(F)C([O-])=O.[Ag+]>[CH2:1]([O:8][C:9]1[CH:10]=[C:11]([C:14]([I:25])=[CH:15][C:16]=1[O:17][CH2:18][C:19]1[CH:24]=[CH:23][CH:22]=[CH:21][CH:20]=1)[CH2:12][OH:13])[C:2]1[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=1

참가 물질

실험 절차

The dibenzyloxybenzyl alcohol 28 (21.44 mmol) and silver trifluoroacetate (21.44 mmol) were suspended in 100 mL of dry chloroform and stirred under argon. A solution of iodine (21.44 mmol) in dry chloroform (50 mL) was added to the suspension dropwise at room temperature. The reaction mixture was then stirred for a further period of 2 h and filtered. The filtrate was washed with 20% sodium thiosulfate solution in water. The organic layer was separated and dried over anhydrous Na2SO4. Filtration was followed by evaporation of the chloroform solution resulting in the pure iodo compound, 3,4-Dibenzyloxy-6-iodobenzyl alcohol (29), as a pale yellow solid in 84% yield.