Methanol → 2-(4-{[(4-Chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-1,3-oxazole-4-carboxylic acid

HRID 43599노트

반응식

HRID 43599 반응식
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][CH:20]=[C:21]([C:23]([O:25]C)=[O:24])[N:22]=3)=[CH:14][C:13]=2[O:27][CH3:28])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+].CO>O1CCCC1>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][CH:20]=[C:21]([C:23]([OH:25])=[O:24])[N:22]=3)=[CH:14][C:13]=2[O:27][CH3:28])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]

참가 물질

5

반응물 3

HCID 887MethanolHCID 3939Lithium HydroxideHCID 67548965Methyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-1,3-oxazole-4-carboxylate

생성물 1

HCID 596154922-(4-{[(4-Chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-1,3-oxazole-4-carboxylic acid수율 62.4%

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매

실험 절차

The same operation as in Example (91d) was performed using methyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-methoxyphenyl)-1,3-oxazole-4-carboxylate obtained in Example (102e) (0.26 g, 0.64 mmol), 2 N lithium hydroxide (3 mL, 6 mmol), methanol (3 mL) and tetrahydrofuran (5 mL), to obtain 156 mg of the title compound as a colorless solid (62%).

출처 및 근거

ORD 기록
ord-b46e496149534ab6a2ca8b7ab9cd3177
출처 데이터셋
uspto-grants-2013_09
특허 번호
US08536197B2

반응 노트

불러오는 중…