Sodium Hydroxide → 2-(Benzyloxy)-5-(pyridin-4-yl)benzoic acid

반응식

[OH-].[Na+].[CH2:3]([O:10][C:11]1[CH:26]=[CH:25][C:24]([C:27]2[CH:32]=[CH:31][N:30]=[CH:29][CH:28]=2)=[CH:23][C:12]=1[C:13]([O:15]CC1C=CC=CC=1)=[O:14])[C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1>O1CCOCC1.CO>[CH2:3]([O:10][C:11]1[CH:26]=[CH:25][C:24]([C:27]2[CH:28]=[CH:29][N:30]=[CH:31][CH:32]=2)=[CH:23][C:12]=1[C:13]([OH:15])=[O:14])[C:4]1[CH:5]=[CH:6][CH:7]=[CH:8][CH:9]=1

참가 물질

실험 절차

An 2 mol/L aqueous solution of sodium hydroxide (1.1 mL) was added to a solution mixture of the obtained benzyl 2-(benzyloxy)-5-(pyridin-4-yl)benzoate (0.29 g) in dioxane (2.9 mL) and methanol (2.9 mL), followed by stirring at room temperature for 1 hour. The solvent was evaporated under reduced pressure, and water was added to the residue. After adjusting the pH to 4 with 6 mol/L hydrochloric acid, ethyl acetate was added thereto. The reaction mixture was filtrated to collect the solid substance to obtain 0.19 g of 2-(benzyloxy)-5-(pyridin-4-yl)benzoic acid as a white solid.