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Sodium Hydroxide → HCID 58822575, 화합물

HRID 459252
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HRID 459252 반응식
C([O:3][C:4](=[O:20])[C@@H:5]([O:18][CH3:19])[CH2:6][C:7]1[CH:12]=[CH:11][C:10]([O:13][CH2:14][CH2:15][CH2:16]Br)=[CH:9][CH:8]=1)C.[OH:21][C:22]1[CH:27]=[CH:26][C:25]([C:28]([C:30]2[CH:39]=[CH:38][C:37]3[C:32](=[CH:33][CH:34]=[CH:35][CH:36]=3)[CH:31]=2)=[O:29])=[CH:24][CH:23]=1.[OH-].[Na+]>>[CH3:19][O:18][C@@H:5]([CH2:6][C:7]1[CH:8]=[CH:9][C:10]([O:13][CH2:14][CH2:15][CH2:16][O:21][C:22]2[CH:27]=[CH:26][C:25]([C:28]([C:30]3[CH:39]=[CH:38][C:37]4[C:32](=[CH:33][CH:34]=[CH:35][CH:36]=4)[CH:31]=3)=[O:29])=[CH:24][CH:23]=2)=[CH:11][CH:12]=1)[C:4]([OH:3])=[O:20]
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

4

반응물 3

HCID 14798Sodium HydroxideHCID 15640646HCID 15640646, 화합물HCID 58822859(2S)-3-[4-(3-Bromopropoxy)-phenyl]-2-methoxy-propionic acid ethyl ester

생성물 1

HCID 58822575HCID 58822575, 화합물

실험 절차

(2S)-3-[4-(3-Bromo-propoxy)-phenyl]-2-methoxy-propionic acid ethyl ester from Example 173, Step A was treated with (4-Hydroxy-phenyl)-naphthalen-2-yl-methanone from Step A under the Standard Procedure J. The compound thus obtained was allowed to react under Standard hydrolysis procedure C (NaOH) to give the title compound. MS(ES) for C30H28O6 [M+H]+: 485.

후처리

  1. customThe compound thus obtained

출처 및 근거

ORD 기록
ord-87c75df8480a4d02aebd5c1ab7af94ea
출처 데이터셋
uspto-grants-2007_03
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07192982B2

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