Benzoyl chloride → HCID 14049623, 화합물

HRID 466134노트

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HRID 466134 반응식
C[Si](C)(C)[O:3][C:4]1[CH:9]=[C:8]([O:10][Si](C)(C)C)[CH:7]=[CH:6][N:5]=1.[C:17](Cl)(=[O:24])[C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=1>ClCCl>[C:17]([O:3][C:4]1[CH:9]=[C:8]([O:10][C:17](=[O:24])[C:18]2[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=2)[CH:7]=[CH:6][N:5]=1)(=[O:24])[C:18]1[CH:23]=[CH:22][CH:21]=[CH:20][CH:19]=1

참가 물질

4

반응물 2

HCID 7412Benzoyl chlorideHCID 21819823HCID 21819823, 화합물

생성물 1

HCID 14049623HCID 14049623, 화합물수율 24.6%

시약·촉매·용매 1

HCID 6344Dichloromethane용매

실험 절차

To 4.0 g of 2,4-bis(trimethylsilyloxy)-pyridine in 50 ml of dichloromethane were added 2.65 g of benzoyl chloride and 0.2 ml of stannic chloride, and the mixture was stirred at room temperature for one hour. The solvent was distilled off and the residue was subjected to silica gel chromatography using ethyl acetate-benzene (2:3) as an eluent to produce 0.74 g of the title compound in a yield of 14.8%.

후처리

  1. distillationThe solvent was distilled off

출처 및 근거

ORD 기록
ord-19ced059d5cf4a31866ca35ad1ec7956
출처 데이터셋
uspto-grants-1992_10
특허 번호
US05155113

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