Water → HCID 14514900, 화합물

HRID 486892노트

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HRID 486892 반응식
[CH2:1]1[O:12][C:11]2[CH:10]=[C:9]3[C:5]([CH2:6][CH2:7][C:8]3=[O:13])=[CH:4][C:3]=2[O:2]1.[H-].[Al+3].[Li+].[H-].[H-].[H-].O.[OH-].[Na+]>O1CCCC1>[CH2:1]1[O:12][C:11]2[CH:10]=[C:9]3[C:5]([CH2:6][CH2:7][CH:8]3[OH:13])=[CH:4][C:3]=2[O:2]1

참가 물질

6

반응물 4

HCID 962Water2회HCID 14798Sodium HydroxideHCID 2483515,6-Methylenedioxy-1-indanoneHCID 21226445Aluminium lithium hydride

생성물 1

HCID 14514900HCID 14514900, 화합물수율 80.1%

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매2회

실험 절차

A solution of 30 g of 5,6-methylenedioxyindan-1-one in 120 ml of tetrahydrofuran was added dropwise to a suspension of 2.4 g of lithium aluminum hydride in 160 ml of anhydrous tetrahydrofuran under cooling with ice. The mixture was stirred at room temperature overnight. 2.4 ml of water, then 2.4 ml of 15% aqueous sodium hydroxide solution and finally 7.2 ml of water were added thereto and insoluble substances were filtered off. The filtrate was distilled and the residue was washed with diisopropyl ether to obtain 24.3 g of the intended compound in the form of faint brown crystals.

후처리

  1. temperatureunder cooling with ice
  2. filtrationinsoluble substances were filtered off
  3. distillationThe filtrate was distilled
  4. washthe residue was washed with diisopropyl ether

출처 및 근거

ORD 기록
ord-55665e2e2b0c4f06a3335d28375cfed3
출처 데이터셋
uspto-grants-1994_03
특허 번호
US05292901

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