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Lithium → HCID 87142787, 화합물

HRID 530182
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HRID 530182 반응식
[F:1][CH:2]([O:7][CH:8](F)[C:9]([F:12])(F)[F:10])[C:3]([F:6])([F:5])[F:4].[CH3:14][Li].[Li]>C(OCC)OCC>[C:9](=[C:8]([O:7][CH:2]([C:3]([F:6])([F:5])[F:4])[F:1])[CH3:14])([F:12])[F:10]
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

5

반응물 3

HCID 3028194LithiumHCID 125199721,1,1,2-Tetrafluoro-2-(1,2,2,2-tetrafluoroethoxy)ethaneHCID 178418348HCID 178418348, 화합물2회

생성물 1

HCID 87142787HCID 87142787, 화합물

시약·촉매·용매 1

HCID 10024Diethoxymethane용매

실험 절차

Another reaction was performed under similar conditions using a 1:2 molar ratio of bis-(1,2,2,2-tetrafluoroethyl)ether (32.5 grams, 0.15 mols) and CH3Li (105 mL of 3.0 M solution of CH3Li in CH2(OC2H5)2, 0.32 mols of the base). 43.1 grams of a crude product liquid was collected. GC analysis demonstrated that the liquid contained 1.5% bis-olefin, 0.4% mono-olefin, 0.1% unreacted starting ether, 4.3% unknown by-product, 7.3% CF2═C(CH3)OCHFCF3 (major by-product discussed above) and 84.5% CH2(OC2H5)2. These reaction conditions demonstrate that doubling the amount of the lithium reagent produces more of the by-product CF2═C(CH3)OCHFCF3 at the expense of the desired mono-olefin.

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후처리

  1. custom43.1 grams of a crude product liquid was collected
  2. customThese reaction conditions

출처 및 근거

ORD 기록
ord-7e98da2aad5f4b10b6e90bc0bdad117d
출처 데이터셋
uspto-grants-2016_05
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US09353038B2

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