[CH3:1][O:2][C:3]1[CH:8]=[CH:7][CH:6]=[C:5]([O:9][CH3:10])[C:4]=1[C:11]1[N:15]([C:16]2[CH:21]=[CH:20][C:19]([C:22](=[O:31])[N:23]([CH3:30])[CH2:24][CH2:25][CH2:26][N:27]([CH3:29])[CH3:28])=[CH:18][C:17]=2[CH:32]([CH3:34])[CH3:33])[N:14]=[C:13]([C:35]([NH:37][C:38]2([C:48]([OH:50])=[O:49])[CH:45]3[CH2:46][CH:41]4[CH2:42][CH:43]([CH2:47][CH:39]2[CH2:40]4)[CH2:44]3)=[O:36])[CH:12]=1.[C:51]([OH:58])(=[O:57])/[CH:52]=[CH:53]\[C:54]([OH:56])=[O:55]>CC(O)C>[C:51]([OH:58])(=[O:57])/[CH:52]=[CH:53]\[C:54]([OH:56])=[O:55].[CH3:10][O:9][C:5]1[CH:6]=[CH:7][CH:8]=[C:3]([O:2][CH3:1])[C:4]=1[C:11]1[N:15]([C:16]2[CH:21]=[CH:20][C:19]([C:22](=[O:31])[N:23]([CH3:30])[CH2:24][CH2:25][CH2:26][N:27]([CH3:28])[CH3:29])=[CH:18][C:17]=2[CH:32]([CH3:34])[CH3:33])[N:14]=[C:13]([C:35]([NH:37][C:38]2([C:48]([OH:50])=[O:49])[CH:39]3[CH2:40][CH:41]4[CH2:42][CH:43]([CH2:44][CH:45]2[CH2:46]4)[CH2:47]3)=[O:36])[CH:12]=10.1 g of the compound obtained in EXAMPLE 1' and 0.017 g of maleic acid are dissolved in the heated state in 2.3 ml of 2-propanol, and the mixture is concentrated under vacuum. The residue is dissolved in 0.3 ml of EtOH, this solution is poured into 30 ml of ether and the precipitate formed is drained. 0.04 g of the expected product is obtained, m.p.=260° C. (dec.).
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