Water → 3-(4-Fluorophenyl)-6-methylpicolinic acid
반응식
[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:9]([C:15]#N)=[N:10][C:11]([CH3:14])=[CH:12][CH:13]=2)=[CH:4][CH:3]=1.[OH-:17].[Na+].[OH2:19]>CO>[F:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:9]([C:15]([OH:19])=[O:17])=[N:10][C:11]([CH3:14])=[CH:12][CH:13]=2)=[CH:4][CH:3]=1참가 물질
5
반응 조건
- 온도
- 100 °C
실험 절차
To the solution of 3-(4-fluorophenyl)-6-methylpicolinonitrile (0.555 g, 2.615 mmol) in MeOH (3 mL) was added NaOH (1.1 g, 27.5 mmol) and H2O (1.8 mL). The mixture was heated at 100° C. for 8 h. The reaction was cooled to rt and acidified to pH-5. The solvent was removed in vacuo. The crude was extracted with MeOH. The solvent was removed in vacuo and the obtained acid was dried in vacuum for next step with no further purification. ESI-MS (m/z): 233 [M+1]+.
후처리
- temperatureThe reaction was cooled to rt
- customThe solvent was removed in vacuo
- extractionThe crude was extracted with MeOH
- customThe solvent was removed in vacuo
- customthe obtained acid was dried in vacuum for next step with no further purification
출처 및 근거
- ORD 기록
- ord-db06a1b42d6e4a128ca34831ff6e42a1
- 출처 데이터셋
- uspto-grants-2016_09
- 특허 번호
- US09440982B2
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