Sodium Hydroxide → 11-(p-Hydroxyphenoxy)undecanoic acid
반응식
[OH:1][C:2]1[CH:23]=[CH:22][C:5]([O:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][C:17]([O:19]CC)=[O:18])=[CH:4][CH:3]=1.[OH-].[Na+]>C(O)C>[OH:1][C:2]1[CH:3]=[CH:4][C:5]([O:6][CH2:7][CH2:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][C:17]([OH:19])=[O:18])=[CH:22][CH:23]=1참가 물질
4
실험 절차
In a 500 ml flask equipped with a stirrer and a condenser were charged 32.2 g of ethyl 11-(p-hydroxyphenoxy)undecanoate synthesized in Synthetic example 2, 100 g of a 10% aqueous sodium hydroxide solution and 100 ml of ethanol, and the mixture was refluxed for 2 hours. After completion of the reaction, the reaction mixture was concentrated, poured into 600 ml of a 2% aqueous hydrochloric acid solution and precipitated crystals were collected by filtration. The resulting crystals were washed with distilled water and recrystallized from acetonitrile to obtain 20.2 g of the title compound.