Formaldehyde → 6-(3-Bromophenyl)-2-hydroxymethyl-3(2H)-pyridazinone

반응식

[Br:1][C:2]1[CH:3]=[C:4]([C:8]2[CH:9]=[CH:10][C:11](=[O:14])[NH:12][N:13]=2)[CH:5]=[CH:6][CH:7]=1.[CH2:15]=[O:16]>Cl.CO>[Br:1][C:2]1[CH:3]=[C:4]([C:8]2[CH:9]=[CH:10][C:11](=[O:14])[N:12]([CH2:15][OH:16])[N:13]=2)[CH:5]=[CH:6][CH:7]=1

참가 물질

실험 절차

2.51 g of 6-(3-bromophenyl)-3(2H)-pyridazinone, 5 ml of a 37% formalin and 2 drops of concentrated hydrochloric acid were dissolved in 50 ml of methanol, and then the solution was heated under reflux for about 7 hours. The mixture was then left to stand overnight, after which it was filtered and the filtrate was concentrated by evaporation under reduced pressure. The resulting residue was extracted with a 1:1 by volume mixture of ethyl acetate and acetone. After distilling the solvent from the extract, there were obtained 1.13 g (yield 40%) of the desired Compound No. 1 in the form of a white solid melting at 228°-229° C.