N,N-Dimethylaniline → Terephthaloyl chloride

반응식

[C:1]([OH:12])(=O)[C:2]1[CH:10]=[CH:9][C:5](C(O)=O)=[CH:4][CH:3]=1.CN(C)C1C=CC=CC=1.[C:22]([Cl:25])(Cl)=[O:23].C(OC)(=O)C1C=CC(C(OC)=O)=CC=1.[Cl:40]CCl>>[C:22]([Cl:25])(=[O:23])[C:5]1[CH:9]=[CH:10][C:2]([C:1]([Cl:40])=[O:12])=[CH:3][CH:4]=1

참가 물질

반응물 5

HCID 949N,N-Dimethylaniline2회

HCID 6344Dichloromethane

HCID 6371Phosgene

HCID 7489Terephthalic Acid

HCID 8441Dimethyl terephthalate

생성물 1

HCID 7488Terephthaloyl chloride수율 90.2%

실험 절차

Following the general procedure in Example 1 for the preparation of the diacid chloride, 8.93 parts of terephthalic acid were added to a mixture of 16.47 parts of N,N-dimethyl aniline and 12.8 parts phosgene in 200 parts dry dichloromethane at 25° to 30° C. The ratio of equivalents of dimethylaniline base/COOH acid group was 1.26. After carrying out the reaction and esterifying the resulting diacid chloride by the procedure described in Example 1, 9.87 parts of a solid containing 95.4% dimethyl terephthalate was obtained corresponding to a 90.2% yield of theory of terephthaloyl chloride formed initially in the reaction.