Lithium Hydroxide → HCID 135540802, 화합물

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[Li+].[OH-].[O:3]=[C:4]1[N:8]([CH:9]2[CH2:14][CH2:13][N:12]([C:15]([O:17][C@H:18]([CH2:39][C:40]3[CH:45]=[C:44]([CH3:46])[C:43]([OH:47])=[C:42]([CH3:48])[CH:41]=3)[C:19]([N:21]3[CH2:26][CH2:25][CH:24]([CH:27]4[CH2:32][CH2:31][N:30]([CH2:33][C:34]([O:36]CC)=[O:35])[CH2:29][CH2:28]4)[CH2:23][CH2:22]3)=[O:20])=[O:16])[CH2:11][CH2:10]2)[N:7]=[C:6]([C:49]2[CH:54]=[CH:53][CH:52]=[CH:51][CH:50]=2)[NH:5]1>O.C1COCC1>[O:3]=[C:4]1[N:8]([CH:9]2[CH2:14][CH2:13][N:12]([C:15]([O:17][C@H:18]([CH2:39][C:40]3[CH:41]=[C:42]([CH3:48])[C:43]([OH:47])=[C:44]([CH3:46])[CH:45]=3)[C:19]([N:21]3[CH2:26][CH2:25][CH:24]([CH:27]4[CH2:32][CH2:31][N:30]([CH2:33][C:34]([OH:36])=[O:35])[CH2:29][CH2:28]4)[CH2:23][CH2:22]3)=[O:20])=[O:16])[CH2:11][CH2:10]2)[N:7]=[C:6]([C:49]2[CH:50]=[CH:51][CH:52]=[CH:53][CH:54]=2)[NH:5]1

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실험 절차

A solution of 1.2 mg (0.05 mmol) LiOH in 2 mL water was added to a solution of 21 mg (0.03 mmol) (R)-2-(1′-ethoxycarbonylmethyl-4,4′-bipiperidinyl-1-yl)-1-(4-hydroxy-3,5-dimethyl-benzyl)-2-oxo-ethyl 4-(5-oxo-3-phenyl-4,5-dihydro-1,2,4-triazol-1-yl)-piperidine-1-carboxylate in 3 mL THF and the reaction mixture was stirred for 1 h at RT. The THF was evaporated down i.vac., the residue was acidified with 1 M HCl and again evaporated down i.vac. The residue was purified by HPLC, the fractions containing the product were combined and lyophilised.