Iodoethane → 2-[4-(1,3-Benzoxazol-2-yl)-2-methoxyphenyl]butanenitrile

반응식

[O:1]1[C:5]2[CH:6]=[CH:7][CH:8]=[CH:9][C:4]=2[N:3]=[C:2]1[C:10]1[CH:15]=[CH:14][C:13]([CH:16]([CH3:19])[C:17]#[N:18])=[C:12]([O:20][CH3:21])[CH:11]=1.O1C2C=CC=CC=2N=[C:23]1C1C=CC(C#N)=C(OC)C=1.ICC>>[O:1]1[C:5]2[CH:6]=[CH:7][CH:8]=[CH:9][C:4]=2[N:3]=[C:2]1[C:10]1[CH:15]=[CH:14][C:13]([CH:16]([CH2:19][CH3:23])[C:17]#[N:18])=[C:12]([O:20][CH3:21])[CH:11]=1

참가 물질

반응물 3

HCID 6340Iodoethane

HCID 101493732-[4-(1,3-Benzoxazol-2-yl)-2-methoxyphenyl]propanenitrile

HCID 219909874-(1,3-Benzoxazol-2-yl)-2-methoxybenzonitrile

생성물 1

HCID 101716882-[4-(1,3-Benzoxazol-2-yl)-2-methoxyphenyl]butanenitrile

실험 절차

Utilizing the general procedure outlined in the synthesis of 2-[4-(1,3-benzoxazol-2-yl)-2-methoxyphenyl]propanenitrile, 4-(1,3-benzoxazol-2-yl)-2-methoxybenzonitrile (300 mg, 1.1 mmol) was reacted with iodoethane (90 μL, 1.1 mmol) to afford the desired 2-[4-(1,3-benzoxazol-2-yl)-2-methoxyphenyl]butanenitrile as a yellow solid: 1H NMR (CDCl3, 300 MHz) δ 7.87–7.84 (d, 1H), 7.79–7.74 (m, 2H), 7.59–7.53 (m, 2H), 7.37–7.34 (m, 2H), 4.22–4.17 (t, 1H), 3.97 (s, 3H), 1.95–1.89 (m, 2H), 1.13–1.08 (t, 3H). MS (ESI) 293 (M+H)+.