Sodium Hydroxide → 3-[4-(Hydroxymethyl)phenyl]propanoic acid

반응식

Cl[CH2:2][C:3]1[CH:13]=[CH:12][C:6]([CH2:7][CH2:8][C:9]([OH:11])=[O:10])=[CH:5][CH:4]=1.[OH-].[Na+].C1C=C(C(C2C=CC(O)=CC=2)C2C=CC([OH:29])=CC=2)C(C(O)=O)=CC=1>O>[OH:29][CH2:2][C:3]1[CH:13]=[CH:12][C:6]([CH2:7][CH2:8][C:9]([OH:11])=[O:10])=[CH:5][CH:4]=1

참가 물질

실험 절차

30 g (0.15 mol) of 4-chloromethyl-hydrocinnamic acid (J. Org, Chem. 26, 148 (1961) in 200 ml of water were neutralized with a 10% sodium hydroxide solution against phenol phthaline. 10% of NaOH (on the whole about 60 ml) were added dropwise, while stirring at reflux temperature, to the solution obtained in the same measure as it was consumed. When the reaction was finished, the mixture was saturated with sodium chloride, acidified with concentrated hydrochloric acid, the product precipitated was suction-filtered and washed with water. Melting point: 124°-126° C.