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Sodium hydride → HCID 9890536, 화합물

HRID 855707
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HRID 855707 반응식
Cl[C:2]1[C:11]2[C:6](=[CH:7][C:8]([O:14][CH2:15][CH2:16][CH2:17][N:18]3[CH2:23][CH2:22][O:21][CH2:20][CH2:19]3)=[C:9]([O:12][CH3:13])[CH:10]=2)[N:5]=[CH:4][N:3]=1.[N:24]1[CH:29]=[CH:28][C:27]([C:30]2[CH2:34][C:33](=[O:35])[NH:32][N:31]=2)=[CH:26][CH:25]=1.[H-].[Na+]>CN(C=O)C>[CH3:13][O:12][C:9]1[CH:10]=[C:11]2[C:6](=[CH:7][C:8]=1[O:14][CH2:15][CH2:16][CH2:17][N:18]1[CH2:23][CH2:22][O:21][CH2:20][CH2:19]1)[N:5]=[CH:4][N:3]=[C:2]2[O:35][C:33]1[CH:34]=[C:30]([C:27]2[CH:28]=[CH:29][N:24]=[CH:25][CH:26]=2)[NH:31][N:32]=1
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

5

반응물 3

HCID 24758Sodium hydrideHCID 118239414-Chloro-6-methoxy-7-(3-morpholin-4-ylpropoxy)quinazolineHCID 132689575-(Pyridin-4-yl)-2,4-dihydro-3H-pyrazol-3-one

생성물 1

HCID 9890536HCID 9890536, 화합물수율 48%

시약·촉매·용매 1

HCID 6228Dimethylformamide용매

실험 절차

Using an analogous procedure to that described for Example 9, 4-chloro-6-methoxy-7-(3-morpholinopropoxy)quinazoline (200 mg, 0.59 mmol), (prepared as described for the starting material in Example 2), was reacted with 3-(4-pyridyl)-4,5-dihydro-1H-pyrazol-5-one (240 mg, 1.5 mmol) in the presence of sodium hydride (59 mg, 1.5 mmol, prewashed with THF) in DMF (3 ml) to give 6-methoxy-7-(3-morpholinopropoxy)-4-(5-(4-pyridyl)pyrazol-3-yloxy)quinazoline (130 mg, 48%).

후처리

  1. custom(prepared

출처 및 근거

ORD 기록
ord-2463644ddd6f4bd0a9a876283f73c098
출처 데이터셋
uspto-grants-2007_08
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07262201B1

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