Hydrochloric Acid → Ethyl(2-ethoxyethyl)phosphinic acid

반응식

[CH2:1]([P:3]([CH2:10][CH2:11][O:12][CH2:13][CH3:14])(=[O:9])[O:4]CCCC)[CH3:2].Cl>>[CH2:1]([P:3]([CH2:10][CH2:11][O:12][CH2:13][CH3:14])(=[O:4])[OH:9])[CH3:2]

참가 물질

반응물 2

HCID 313Hydrochloric Acid

HCID 46241032Butyl ethyl(2-ethoxyethyl)phosphinate

생성물 1

HCID 46235414Ethyl(2-ethoxyethyl)phosphinic acid수율 94%

반응 조건

온도: 90 °C

실험 절차

In a stirred apparatus, 222 g (1 mol) of butyl ethyl(2-ethoxyethyl)phosphinate (produced as in Example 7) are dissolved in 200 ml (2 mol) of concentrated hydrochloric acid. The efficiently stirred mixture is heated to about 90° C. and reacted at that temperature for about 8 hours. The water is then completely distilled off in vacuo. The residue is taken up in acetic acid and extracted. The solvent of the filtrate is removed in vacuo to obtain 156 g (94% of theory) of ethyl-(2-ethoxyethyl)phosphinic acid as oil.

후처리

customreacted at that temperature for about 8 hours
distillationThe water is then completely distilled off in vacuo
extractionextracted
customThe solvent of the filtrate is removed in vacuo

출처 및 근거

ORD 기록: ord-b9e2c79d620845b892b03ee8162c9bde
출처 데이터셋: uspto-grants-2015_03
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US08987489B2

반응 노트

불러오는 중…