Hydrochloric Acid → 5-(4-chlorophenyl)furan-2-carbonyl Chloride

반응식

[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[O:12][C:11]([C:13]([OH:15])=O)=[CH:10][CH:9]=2)=[CH:4][CH:3]=1.O=S(Cl)[Cl:18].Cl>>[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[O:12][C:11]([C:13]([Cl:18])=[O:15])=[CH:10][CH:9]=2)=[CH:4][CH:3]=1

참가 물질

반응물 3

HCID 313Hydrochloric Acid

HCID 24386Thionyl Chloride

HCID 7266935-(4-Chlorophenyl)-2-furoic acid

생성물 1

HCID 27719705-(4-chlorophenyl)furan-2-carbonyl Chloride

실험 절차

A mixture of 56 g. (0.25 mole) of 5-(p-chlorophenyl)-2-furoic acid and 100 ml. of SOCl2 is refluxed for 31/2 hours so that HCl gas evolves and there is dissolution. The SOCl2 is removed on a rotary evaporator. Benzene is added to the solid residue and is then removed on the rotary evaporator to give 5-(p-chlorophenyl)-2-furoyl chloride.