Sodium Hydroxide → HCID 71268658, 화합물

HRID 929367노트

반응식

HRID 929367 반응식
[F:1][C:2]1[CH:7]=[CH:6][C:5]([N:8](S(CCC)(=O)=O)[S:9]([CH2:12][CH2:13][CH3:14])(=[O:11])=[O:10])=[CH:4][C:3]=1[C:21]([C:23]1[CH:24]=[C:25]2[C:30](=[CH:31][CH:32]=1)[N:29]=[CH:28][CH:27]=[N:26]2)=[O:22].[OH-].[Na+]>CO>[F:1][C:2]1[CH:7]=[CH:6][C:5]([NH:8][S:9]([CH2:12][CH2:13][CH3:14])(=[O:11])=[O:10])=[CH:4][C:3]=1[C:21]([C:23]1[CH:24]=[C:25]2[C:30](=[CH:31][CH:32]=1)[N:29]=[CH:28][CH:27]=[N:26]2)=[O:22]

참가 물질

4

실험 절차

To a solution of N-(4-fluoro-3-(quinoxaline-6-carbonyl)phenyl)-N-(propylsulfonyl)propane-1-sulfonamide (50 mg, 0.10 mmol, 1.0 eq.) in MeOH (10 mL) was added NaOH aqueous solution (1 N, 0.22 mL, 0.22 mmol, 2.2 eq.). The resulting mixture was stirred at it for 1 h, then concentrated. The resulting residue was purified by flash column chromatography (PE/EA=1/1, v/v) to afford N-(4-fluoro-3-(quinoxaline-6-carbonyl)phenyl)propane-1-sulfonamide (33.4 mg, 89.5%). LRMS (M+H+) m/z calculated 374.1, found 374.1. 1H NMR (CDCl3, 400 MHz) δ 8.94-8.97 (dd, 2 H), 8.46-8.47 (m, 1 H), 8.31-8.34 (m, 1 H), 8.23-8.25 (m, 1 H), 7.50-7.54 (m, 1 H), 7.46-7.48 (m, 1 H), 7.19-7.23 (t, 1 H), 6.80 (s, 1 H), 3.10-3.14 (m, 2 H), 1.86-1.92 (m, 2 H), 1.04-1.08 (t, 3 H).

후처리

  1. concentrationconcentrated
  2. customThe resulting residue was purified by flash column chromatography (PE/EA=1/1

출처 및 근거

ORD 기록
ord-8da6cc9cb2d24947bd7c9d9688194e68
출처 데이터셋
uspto-grants-2016_03
특허 번호
US09295671B2

반응 노트

불러오는 중…