Sodium Iodide → Benzyl iodide
반응식
[CH2:1](Cl)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[I-:9].[Na+].[CH3:11][C:12]1[CH:13]=[N:14][CH:15]=[CH:16][C:17]=1[CH2:18][CH2:19][CH3:20]>CC(C)=O>[CH2:1]([I:9])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[I-:9].[CH2:1]([N+:14]1[CH:15]=[CH:16][C:17]([CH2:18][CH2:19][CH3:20])=[C:12]([CH3:11])[CH:13]=1)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1참가 물질
6
실험 절차
A solution of benzyl iodide in acetone was prepared from benzyl chloride (823 g.) and sodium iodide (975 g.). 3-Methyl-4-propylpyridine (879 g.) was added and the mixture was stirred at room temperature. Crystallization of the product from acetone-isopropyl acetate afforded 1-benzyl-3-methyl-4-propylpyridinium iodide in two crops (1334 g. and 162 g.), which melted at 94°-95° C.