Hydrogen Bromide → 5-Bromo-5-octylbarbituric acid

반응식

[CH2:1]([CH:9]1[C:14](=[O:15])[NH:13][C:12](=[O:16])[NH:11][C:10]1=[O:17])[CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH3:8].[BrH:18].BrBr>O>[Br:18][C:9]1([CH2:1][CH2:2][CH2:3][CH2:4][CH2:5][CH2:6][CH2:7][CH3:8])[C:14](=[O:15])[NH:13][C:12](=[O:16])[NH:11][C:10]1=[O:17]

참가 물질

반응 조건

온도: 2.5 °C

실험 절차

To a suspension of 5-octylbarbituric Acid (20 g) in 120 ml of water, cooled at 0-5° C., are added 12 ml of 48% hydrobromic acid and successively are dropped 4.72 ml of bromine. Ater 2 hours under stirring, the white solid which separated is recovered by filtration, washed with water and partitioned between 200 ml of diethyl ether and 100 ml of water. The aqueous phase is extracted with additional 50 ml of diethyl ether. The pooled organic phases are washed with 75 ml of saturated aqueous solution of sodium chloride, dried over sodium sulfate and concentrated to dryness. 25.8 g of the product as white solid are obtained.