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HRID1016312

反应详情

EQUATION

反应方程式

HRID 1016312 的结构方程式

REACTANTS

反应物

2
反应SMILES：Cl.ClCc1ccncc1
HCID74570

4-(Chloromethyl)pyridinium chloride

C6H7Cl2N

反应SMILES：O=c1c(Cc2cccnc2)cn2c3c(cc(O)cc13)Sc1ccc(Br)cc1-2
HCID12021105

未命名化合物

PRODUCTS

产物

1
反应SMILES：O=c1c(Cc2cccnc2)cn2c3c(cc(OCc4ccncc4)cc13)Sc1ccc(Br)cc1-2
HCID12021110

未命名化合物

收率 54.1%

PROCEDURE

实验过程

According to Example 34, the compound (150 mg) produced in Example 37 was reacted with 4-chloromethylpyridine hydrochloride (84 mg) to obtain the title compound (98 mg; 54%).