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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1016312Generated: October 31, 2026

4-(Chloromethyl)pyridinium chloride → 10-bromo-2-(3-pyridylmethyl)-5-(4-pyridylmethyloxy)-3H-pyrido[3,2,1-kl]phenothiazin-3-one

https://huagongshe.com/reaction/1016312

Reaction equation

Participants

RoleNameHCIDCharge
Reactant4-(Chloromethyl)pyridinium chlorideHCID 74570—
Reactant10-bromo-5-hydroxy-2-(3-pyridylmethyl)-3H-pyrido[3,2,1-kl]phenothiazin-3-oneHCID 12021105—
Product10-bromo-2-(3-pyridylmethyl)-5-(4-pyridylmethyloxy)-3H-pyrido[3,2,1-kl]phenothiazin-3-oneHCID 1202111054.1%

Reaction Steps

According to Example 34, the compound (150 mg) produced in Example 37 was reacted with 4-chloromethylpyridine hydrochloride (84 mg) to obtain the title compound (98 mg; 54%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06476021B1
Source datasetuspto-grants-2002_11
ORD IDord-48d24e38dcf54eca82766fcb9ae5e0af
Source noteuspto-grants-2002_11