HRID1036998

反应详情

EQUATION

反应方程式

HRID 1036998 的结构方程式

PROCEDURE

实验过程

The preparation of the title compound takes place in analogy to the synthesis of the compound from Example 1 starting with 49.1 mg (0.13 mmol) of the compound from Example 20A. 40.9 mg (71% of theory) of the title compound are obtained.