HRID1042465

反应详情

EQUATION

反应方程式

HRID 1042465 的结构方程式

PROCEDURE

实验过程

2-Ethylamino-4-trifluoromethyl-benzaldehyde (22 mg) was reacted with methyl (triphenylphosphoranylidene)acetate (49 mg, 0.14 mmol) at 110° C. overnight as described above to yield 3-(2-ethylamino-4-trifluoromethyl-phenyl)-acrylic acid methyl ester. 3-(2-Ethylamino-4-trifluoromethyl-phenyl)-acrylic acid methyl ester was reacted with 1N LiOH (5 ml) as described above to yield the title compound (20.2 mg)