Lithium Hydroxide → 3-(2-Ethylamino-4-trifluoromethyl-phenyl)-acrylic acid
Reaction equation
C[O:2][C:3](=[O:19])[CH:4]=[CH:5][C:6]1[CH:11]=[CH:10][C:9]([C:12]([F:15])([F:14])[F:13])=[CH:8][C:7]=1[NH:16][CH2:17][CH3:18].[Li+].[OH-]>>[CH2:17]([NH:16][C:7]1[CH:8]=[C:9]([C:12]([F:13])([F:15])[F:14])[CH:10]=[CH:11][C:6]=1[CH:5]=[CH:4][C:3]([OH:19])=[O:2])[CH3:18]Participants
3
Procedure
2-Ethylamino-4-trifluoromethyl-benzaldehyde (22 mg) was reacted with methyl (triphenylphosphoranylidene)acetate (49 mg, 0.14 mmol) at 110° C. overnight as described above to yield 3-(2-ethylamino-4-trifluoromethyl-phenyl)-acrylic acid methyl ester. 3-(2-Ethylamino-4-trifluoromethyl-phenyl)-acrylic acid methyl ester was reacted with 1N LiOH (5 ml) as described above to yield the title compound (20.2 mg)
Sources & evidence
- ORD record
- ord-0f1a21bcf362444093f4d1fbfb669ad1
- Source dataset
- uspto-grants-2013_10
- Patent number
- US08557872B2
Reaction notes
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