Lithium Hydroxide → 3-(4-Fluoro-2-propoxy-phenyl)-acrylic acid

HRID 1042479Notes

Reaction equation

HRID 1042479 reaction equation
C[O:2][C:3](=[O:17])[CH:4]=[CH:5][C:6]1[CH:11]=[CH:10][C:9]([F:12])=[CH:8][C:7]=1[O:13][CH2:14][CH2:15][CH3:16].[Li+].[OH-]>>[F:12][C:9]1[CH:10]=[CH:11][C:6]([CH:5]=[CH:4][C:3]([OH:17])=[O:2])=[C:7]([O:13][CH2:14][CH2:15][CH3:16])[CH:8]=1

Participants

3

Reactant 2

HCID 3939Lithium HydroxideHCID 668556023-(4-Fluoro-2-propoxy-phenyl)-acrylic acid methyl ester

Product 1

HCID 668560523-(4-Fluoro-2-propoxy-phenyl)-acrylic acidYield 92.7%

Procedure

3-(4-Fluoro-2-propoxy-phenyl)-acrylic acid methyl ester (134 mg, 0.563 mmol) was reacted with aqueous 1N LiOH (5 ml) as described above to yield title compound (117 mg, 92%).

Sources & evidence

ORD record
ord-08a07868674249218302032031e99d4b
Source dataset
uspto-grants-2013_10
Patent number
US08557872B2

Reaction notes

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