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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1042491Generated: October 25, 2026

Butyl iodide → 3-(2-Butoxy-4-fluoro-phenyl)-acrylic acid methyl ester

https://huagongshe.com/reaction/1042491

Reaction equation

Participants

RoleNameHCIDCharge
ReactantButyl iodideHCID 10962—
ReactantPotassium CarbonateHCID 11430—
Reactant3-(4-Fluoro-2-hydroxy-phenyl)-acrylic acid methyl esterHCID 66857693—
Product3-(2-Butoxy-4-fluoro-phenyl)-acrylic acid methyl esterHCID 66856235—

Reaction Steps

3-(4-Fluoro-2-hydroxy-phenyl)-acrylic acid methyl ester (106 mg) was reacted with K2CO3 (125 mg) and butyl iodide (0.1 ml) at 80° C. for 3 hrs as described above to yield title compound (121 mg).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08557872B2
Source datasetuspto-grants-2013_10
ORD IDord-f462d52d93c9446bb9abba344108b4a8
Source noteuspto-grants-2013_10