Butyl iodide → 3-(2-Butoxy-4-fluoro-phenyl)-acrylic acid methyl ester
Reaction equation
[CH3:1][O:2][C:3](=[O:14])[CH:4]=[CH:5][C:6]1[CH:11]=[CH:10][C:9]([F:12])=[CH:8][C:7]=1[OH:13].C([O-])([O-])=O.[K+].[K+].[CH2:21](I)[CH2:22][CH2:23][CH3:24]>>[CH3:1][O:2][C:3](=[O:14])[CH:4]=[CH:5][C:6]1[CH:11]=[CH:10][C:9]([F:12])=[CH:8][C:7]=1[O:13][CH2:21][CH2:22][CH2:23][CH3:24]Participants
4
Procedure
3-(4-Fluoro-2-hydroxy-phenyl)-acrylic acid methyl ester (106 mg) was reacted with K2CO3 (125 mg) and butyl iodide (0.1 ml) at 80° C. for 3 hrs as described above to yield title compound (121 mg).
Sources & evidence
- ORD record
- ord-f462d52d93c9446bb9abba344108b4a8
- Source dataset
- uspto-grants-2013_10
- Patent number
- US08557872B2
Reaction notes
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