HRID104798

反应详情

EQUATION

反应方程式

HRID 104798 的结构方程式

REACTANTS

反应物

3

结构：Cl

Hydrochloric Acid

ClH

结构：CO

Methanol

CH4O

结构：O=C(O)C1NCCc2c1[nH]c1ccccc21

2,3,4,9-Tetrahydro-1H-pyrido(3,4-b)indole-1-carboxylic acid

C12H12N2O2

PRODUCTS

生成物

1

结构：COC(=O)C1NCCc2c1[nH]c1ccccc21

2,3,4,9-Tetrahydro-1H-beta-carboline-1-carboxylic acid methyl ester

C13H14N2O2