HRID1055670

反应详情

EQUATION

反应方程式

HRID 1055670 的结构方程式

PROCEDURE

实验过程

70 mg (0.14 mmol) of the compound of Example 8A and 51 mg (0.14 mmol) of the compound of Example 22A were reacted analogously to the procedure of Example 48A. This gave 83 mg (88% pure, 83% of theory) of the title compound.