HRID1055671

反应详情

EQUATION

反应方程式

HRID 1055671 的结构方程式

PROCEDURE

实验过程

70 mg (0.17 mmol) of the compound of Example 9A and 78 mg (0.17 mmol) of the compound of Example 17A were reacted and worked up analogously to the procedure of Example 48A. This gave 125 mg (95% of theory) of the title compound.