HRID1055688

反应详情

EQUATION

反应方程式

HRID 1055688 的结构方程式

PROCEDURE

实验过程

80 mg (0.16 mmol) of the compound of Example 60A and 66 mg (0.24 mmol) of the compound of Example 23A were reacted with one another analogously to Example 48A. In deviation from the work-up described therein, here, the mixture was separated directly into its components by preparative HPLC (Method 21). The product-containing fractions were concentrated under reduced pressure and the residue was dried under high vacuum. This gave 84 mg (64% of theory, 80% pure) of the title compound.

WORKUP

后处理

  1. customhere, the mixture was separated directly into its components by preparative HPLC (Method 21)
  2. concentrationThe product-containing fractions were concentrated under reduced pressure
  3. customthe residue was dried under high vacuum