HRID1055737

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：CC(C)(C)c1cc(CN2CCCC2)cc(C(=O)O)c1.O=C(O)C(F)(F)F

HCID89699809

未命名化合物

HCID89700023

未命名化合物

PRODUCTS

生成物

结构：Cc1ccc(NC(=O)c2cc(CN3CCCC3)cc(C(C)(C)C)c2)cc1-n1ccn2nc(-c3cccnc3)cc12

HCID89699759

未命名化合物

PROCEDURE

实验过程

35 mg (0.12 mmol) of the compound of Example 6A and 47 mg (0.12 mmol) of the compound of Example 22A were reacted and worked up analogously to the procedure of Example 16. This gave 55 mg (95% pure, 81% of theory) of the title compound.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-f938a31b79ff49c0b537506c507a0489
来源数据集: uspto-grants-2016_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US09394309B2
来源说明: uspto-grants-2016_07

反应 SMILES

[CH3:1][C:2]1[CH:8]=[CH:7][C:5]([NH2:6])=[CH:4][C:3]=1[N:9]1[C:16]2[N:12]([N:13]=[C:14]([C:17]3[CH:18]=[N:19][CH:20]=[CH:21][CH:22]=3)[CH:15]=2)[CH:11]=[CH:10]1.FC(F)(F)C(O)=O.[C:30]([C:34]1[CH:35]=[C:36]([CH:40]=[C:41]([CH2:43][N:44]2[CH2:48][CH2:47][CH2:46][CH2:45]2)[CH:42]=1)[C:37](O)=[O:38])([CH3:33])([CH3:32])[CH3:31]>>[C:30]([C:34]1[CH:35]=[C:36]([CH:40]=[C:41]([CH2:43][N:44]2[CH2:45][CH2:46][CH2:47][CH2:48]2)[CH:42]=1)[C:37]([NH:6][C:5]1[CH:7]=[CH:8][C:2]([CH3:1])=[C:3]([N:9]2[C:16]3[N:12]([N:13]=[C:14]([C:17]4[CH:18]=[N:19][CH:20]=[CH:21][CH:22]=4)[CH:15]=3)[CH:11]=[CH:10]2)[CH:4]=1)=[O:38])([CH3:33])([CH3:31])[CH3:32]