HRID1055742

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID89699812

未命名化合物

结构：Cc1cc(F)c(N)cc1-n1ccn2nc(-c3cccnc3)cc12

HCID89700032

未命名化合物

PRODUCTS

生成物

结构：Cc1cc(F)c(NC(=O)c2cc(C#N)cc(S(F)(F)(F)(F)F)c2)cc1-n1ccn2nc(-c3cccnc3)cc12

HCID89700090

未命名化合物

PROCEDURE

实验过程

55 mg (0.18 mmol) of the compound of Example 12A and 58 mg (85% pure, 0.18 mmol) of the compound of Example 23A were reacted and worked up analogously to the procedure of Example 38. This gave 43 mg (42% of theory) of the title compound.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-9b2c1f259afd4b599ab8f3adef7669c8
来源数据集: uspto-grants-2016_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US09394309B2
来源说明: uspto-grants-2016_07

反应 SMILES

[F:1][C:2]1[CH:8]=[C:7]([CH3:9])[C:6]([N:10]2[C:17]3[N:13]([N:14]=[C:15]([C:18]4[CH:19]=[N:20][CH:21]=[CH:22][CH:23]=4)[CH:16]=3)[CH:12]=[CH:11]2)=[CH:5][C:3]=1[NH2:4].[C:24]([C:26]1[CH:27]=[C:28]([CH:32]=[C:33]([S:35]([F:40])([F:39])([F:38])([F:37])[F:36])[CH:34]=1)[C:29](O)=[O:30])#[N:25]>>[C:24]([C:26]1[CH:27]=[C:28]([CH:32]=[C:33]([S:35]([F:39])([F:40])([F:36])([F:37])[F:38])[CH:34]=1)[C:29]([NH:4][C:3]1[CH:5]=[C:6]([N:10]2[C:17]3[N:13]([N:14]=[C:15]([C:18]4[CH:19]=[N:20][CH:21]=[CH:22][CH:23]=4)[CH:16]=3)[CH:12]=[CH:11]2)[C:7]([CH3:9])=[CH:8][C:2]=1[F:1])=[O:30])#[N:25]