HRID1056110

反应详情

EQUATION

反应方程式

HRID 1056110 的结构方程式

PROCEDURE

实验过程

1-(6-Fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone (610b) (740 mg, 60% yield) as a light yellow solid was prepared according to the procedure described for Intermediate 605b, using 8-bromo-7-fluoro-3-methyl-N-(1-methylcyclopropyl)quinoxalin-2-amine (610a) (1.39 g, 4.49 mmol) as the starting material. m/z (ESI, +ve ion) 274.2 (M+H)+.