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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1056110Generated: October 31, 2026

8-bromo-7-fluoro-3-methyl-N-(1-methylcyclopropyl)quinoxalin-2-amine → 1-(6-Fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone

https://huagongshe.com/reaction/1056110

Reaction equation

Participants

RoleNameHCIDCharge
Reactant8-bromo-7-fluoro-3-methyl-N-(1-methylcyclopropyl)quinoxalin-2-amineHCID 89782048—
Reactant1-(3-(Tert-butylamino)-6-fluoro-2-methylquinoxalin-5-yl)ethanoneHCID 89782133—
Product1-(6-Fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanoneHCID 8978187460%

Reaction Steps

1-(6-Fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone (610b) (740 mg, 60% yield) as a light yellow solid was prepared according to the procedure described for Intermediate 605b, using 8-bromo-7-fluoro-3-methyl-N-(1-methylcyclopropyl)quinoxalin-2-amine (610a) (1.39 g, 4.49 mmol) as the starting material. m/z (ESI, +ve ion) 274.2 (M+H)+.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09394297B2
Source datasetuspto-grants-2016_07
ORD IDord-26296aaf23fb46bb98d10deb07336ca2
Source noteuspto-grants-2016_07