HRID1056111

反应详情

EQUATION

反应方程式

HRID 1056111 的结构方程式

PROCEDURE

实验过程

2-Bromo-1-(6-fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone (610) (846 mg, 56% yield) as a light yellow solid was prepared according to the procedure described for Intermediate 605, using 1-(6-fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone (610b) (1.18 g, 4.31 mmol) as the starting material. m/z (ESI, +ve ion) 352.1/354.1 (M+H)+.