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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1056111Generated: November 1, 2026

1-(6-Fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone → 2-Bromo-1-(6-fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone

https://huagongshe.com/reaction/1056111

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1-(6-Fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanoneHCID 89781874—
Reactant2-Bromo-1-(3-(tert-butylamino)-6-fluoro-2-methylquinoxalin-5-yl)ethanoneHCID 89781926—
Product2-Bromo-1-(6-fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanoneHCID 8978213656%

Reaction Steps

2-Bromo-1-(6-fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone (610) (846 mg, 56% yield) as a light yellow solid was prepared according to the procedure described for Intermediate 605, using 1-(6-fluoro-2-methyl-3-((1-methylcyclopropyl)amino)quinoxalin-5-yl)ethanone (610b) (1.18 g, 4.31 mmol) as the starting material. m/z (ESI, +ve ion) 352.1/354.1 (M+H)+.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09394297B2
Source datasetuspto-grants-2016_07
ORD IDord-3c6b873cd9c447bf8367d6aca606b726
Source noteuspto-grants-2016_07