Methyl iodide → Ethyl 2-(2-naphthyl)propanoate
Reaction equation
[CH:1]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[CH:4]=[CH:3][C:2]=1[CH2:11][C:12]([O:14][CH2:15][CH3:16])=[O:13].[CH3:17][Si]([N-][Si](C)(C)C)(C)C.[Li+].CI>>[CH:1]1[C:10]2[C:5](=[CH:6][CH:7]=[CH:8][CH:9]=2)[CH:4]=[CH:3][C:2]=1[CH:11]([CH3:17])[C:12]([O:14][CH2:15][CH3:16])=[O:13]Participants
4
Procedure
5 g (23 mmol) of ethyl 2-naphthylacetate, 23.3 mL (1.0 M, 23 mmol) of lithium bis(trimethylsilyl)amide, and 1.5 mL (24 mmol) of methyl iodide were reacted as described in Preparation 11 to yield 5.71 g of a dark oil. Chromatography eluting with a solvent gradient of hexane to hexane/ethyl acetate 19:1 gave the title compound 2.85 g (54%).
Workup
- customas described in Preparation 11
Sources & evidence
- ORD record
- ord-f1af289b623b4ff5b9061e33383ad75b
- Source dataset
- uspto-grants-2003_02
- Patent number
- US06521605B1
Reaction notes
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