9,9-Dichloro-9-silafluorene → 4-(3',5'-Bis-[t-butyl]phenyl)2-isopropylindene

HRID 1071200Notes

Reaction equation

HRID 1071200 reaction equation
Cl[Si]1(Cl)C2C=CC=CC=2C2C1=CC=CC=2.[C:16]([C:20]1[CH:21]=[C:22]([C:30]2[CH:38]=[CH:37][CH:36]=[C:35]3[C:31]=2[CH:32]=[C:33]([CH:39]([CH3:41])[CH3:40])[CH2:34]3)[CH:23]=[C:24]([C:26]([CH3:29])([CH3:28])[CH3:27])[CH:25]=1)([CH3:19])([CH3:18])[CH3:17].[Li]>C1COCC1>[C:16]([C:20]1[CH:21]=[C:22]([C:30]2[CH:38]=[CH:37][CH:36]=[C:35]3[C:31]=2[CH:32]=[C:33]([CH:39]([CH3:41])[CH3:40])[CH2:34]3)[CH:23]=[C:24]([C:26]([CH3:29])([CH3:28])[CH3:27])[CH:25]=1)([CH3:17])([CH3:18])[CH3:19]

Participants

4

Procedure

9,9-Dichloro-9-silafluorene (1.1 g, 8.5 mmol) was dissolved in 80 mL of THF. To this solution was slowly added lithium 4-(3′,5′-di-t-butylphenyl)-2-isopropylindene (3.0 g, 8.5 mmol) as a dry powder and the solution was stirred overnight. After this time, the solvent was removed in vacuo and the residue was taken up in diethyl ether. The solution as filtered through frit to remove LiCl and the solvent was removed in vacuo and used as a crude product (3.9 g) for the next step.

Workup

  1. customAfter this time, the solvent was removed in vacuo
  2. filtrationThe solution as filtered through frit
  3. customto remove LiCl
  4. customthe solvent was removed in vacuo

Sources & evidence

ORD record
ord-aa602fb0935642edb43900b70081da35
Source dataset
uspto-grants-2005_06
Patent number
US06903229B2

Reaction notes

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