Ethanol → 10,11-Dihydro-3-methoxy-8-(methylthio)-dibenzo thiepin-10-ol
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[CH:5][C:6]2[CH2:12][C:11](=O)[C:10]3[CH:14]=[C:15]([S:18][CH3:19])[CH:16]=[CH:17][C:9]=3[S:8][C:7]=2[CH:20]=1.C([OH:23])C.[BH4-].[Na+]>O>[CH3:1][O:2][C:3]1[CH:4]=[CH:5][C:6]2[C:12]3[CH2:11][CH:10]([OH:23])[CH:14]=[C:15]([S:18][CH3:19])[C:16]=3[CH:17]=[CH:9][S:8][C:7]=2[CH:20]=1Participants
5
Procedure
17.8 G. of 3-methoxy-8-(methylthio)-dibenzo[b,f]thiepin-10(11H)-one is suspended in 150 ml. of ethanol and reacted with 38 g. of sodium borohydride. The reaction mixture is stirred for 90 minutes, and subsequently treated with water and extracted with ether. The organic phase is washed with water, dried over magnesium sulfate and evaporated, whereby there is obtained 10,11-dihydro-3-methoxy-8-(methylthio)-dibenzo[d,f]thiepin-10-ol having a melting point of 122°-124°.
Workup
- extractionextracted with ether
- washThe organic phase is washed with water
- dry with materialdried over magnesium sulfate
- customevaporated
Sources & evidence
- ORD record
- ord-bee840270add48898f1237dbb4de0ce9
- Source dataset
- uspto-grants-1976_05
- Patent number
- US03954764
Reaction notes
Loading…