Diisopropyl Ether → HCID 15839962, compound

HRID 1079451Notes

Reaction equation

[N+:1]([C:4]1[CH:15]=[CH:14][CH:13]=[CH:12][C:5]=1[O:6][CH:7]([CH3:11])[C:8]([OH:10])=O)([O-:3])=[O:2].[N+]([O-])(O)=O.[O:20]([CH2:24][CH2:25][NH2:26])[N+:21]([O-:23])=[O:22].C(OC(C)C)(C)C>>[O:20]([CH2:24][CH2:25][NH:26][C:8](=[O:10])[CH:7]([O:6][C:5]1[CH:12]=[CH:13][CH:14]=[CH:15][C:4]=1[N+:1]([O-:3])=[O:2])[CH3:11])[N+:21]([O-:23])=[O:22]

Participants

Reactant 3

HCID 7914Diisopropyl Ether

HCID 78397Ethanol, 2-amino-, 1-nitrate, nitrate (1:1)

HCID 2798552-(2-nitrophenoxy)propanoic acid

Product 1

HCID 15839962HCID 15839962, compoundYield 42.4%

Procedure

Following a similar treatment to that in Example 2 and using 0.75 g of 2-(2-nitrophenoxy)propionic acid and 0.6 g of 2-nitroxyethylamine nitrate, 0.45 g of the title compound was obtained as pale yellow needles (solvent for recrystallization; diisopropyl ether).

Sources & evidence

ORD record: ord-0c5e87d2d99547c2be0508c633de6d28
Source dataset: uspto-grants-1996_12
DOI: 10.6084/m9.figshare.5104873.v1
Patent number: US05580893

Reaction notes

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