Methanol → 3-(2-Fluoroethoxy)-phenol
Reaction equation
[F:1][CH2:2][CH2:3][O:4][C:5]1[CH:6]=[C:7]([CH:10]=[CH:11][CH:12]=1)C=O.ClC1C=C(C=CC=1)C(OO)=[O:18].[OH-].[Na+].CO>C(Cl)Cl>[OH:18][C:7]1[CH:6]=[C:5]([O:4][CH2:3][CH2:2][F:1])[CH:12]=[CH:11][CH:10]=1Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
In a manner similar to that described by Godfrey et al., (J. Chem. Soc. Perkin I, 1353-1354 (1974), the reaction of 7.0 grams (0.042 mole) of 3-(2-fluoroethoxy)benzaldehyde with 3-chloroperoxybenzoic acid (14.0 grams of 75% technical, 0.061 mole) in 100 ml of dry methylene chloride followed by treatment with an aqueous, 15% sodium hydroxide solution and methanol yielded 5.0 grams of 2-fluoroethyl 3-hydroxyphenyl ether as an oil.
Sources & evidence
- ORD record
- ord-172a7cbd501d4d7d8d2801003620d185
- Source dataset
- uspto-grants-1990_10
- Patent number
- US04960884
Reaction notes
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